C++ Language MCQs with Answers [ 4320702 ]
Here are C++ MCQs with answers and explanations:
What is the output of the following code?
int x = 5;
cout << x++ << ++x << x;
Answer: 567
Explanation: The first cout statement outputs the value of x (5), then increments x to 6. The second cout statement increments x to 7, then outputs the value of x (7). The third cout statement outputs the value of x (7).
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What is the output of the following code?
int x = 5;
cout << ++x << x++ << x;
Answer: 678
Explanation: The first cout statement increments x to 6, then outputs the value of x (6). The second cout statement outputs the value of x (6), then increments x to 7. The third cout statement outputs the value of x (7).
What is the output of the following code?
int x = 5;
cout << x << x << x;
Answer: 555
Explanation: All three cout statements output the value of x (5).
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What is the output of the following code?
int x = 5;
cout << x << “ “ << ++x << “ “ << x++;
Answer: 5 6 6
Explanation: The first cout statement outputs the value of x (5), followed by a space. The second cout statement increments x to 6, then outputs the value of x (6), followed by a space. The third cout statement outputs the value of x (6), then increments x to 7.
What is the output of the following code?
int x = 5;
int y = 7;
cout << (x > y ? x : y);
Answer: 7
Explanation: The ternary operator (x > y ? x : y) evaluates to y because x is not greater than y.
What is the output of the following code?
int x = 5;
int y = 7;
cout << (x < y ? x++ : y++);
cout << x << y;
Answer: 57
Explanation: The ternary operator (x < y ? x++ : y++) evaluates to x++ because x is less than y. The first cout statement outputs the value of x (5), then increments x to 6. The second cout statement outputs the values of x (6) and y (7).
What is the output of the following code?
int x = 5;
int y = 7;
cout << (x > y ? x++ : y++);
cout << x << y;
Answer: 78
Explanation: The ternary operator (x > y ? x++ : y++) evaluates to y++ because x is not greater than y. The first cout statement outputs the value of y (7), then increments y to 8. The second cout statement outputs the values of x (5) and y (8).
What is the output of the following code?
int x = 5;
int y = 7;
cout << (x > y ? x++ : ++y);
cout << x << y;
Answer: 8 6 8
Explanation: The ternary operator (x > y ? x++ : ++y) evaluates to ++y because x is not greater than y. The first cout statement outputs the value of y (8), then increments y to 9. The second cout statement outputs the values of x (6) and y (9).
What is the output of the following code?
int x = 5;
int y = 7;
cout << (x < y ? x++ : ++y);
cout << x << y;
Answer: 6 6 8
Explanation: The ternary operator (x < y ? x++ : ++y) evaluates to x++ because x is less than y. The first cout statement outputs the value of x (6), then increments x to 7. The second cout statement outputs the values of x (7) 10. What is the output of the following code?
int x = 5;
int y = 7;
int z = 9;
cout << (x > y ? (y > z ? x : y) : (y < z ? y : x));
Answer: 5
Explanation: The nested ternary operator evaluates to x because x is not greater than y, and y is not less than z. Therefore, the outer ternary operator evaluates to x. The cout statement outputs the value of x (5).
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